<PRE><B>Question 182041</B>
Do you want to factor this? Please post full instructions




Looking at the expression {{{4w^2+19w-5}}}, we can see that the first coefficient is {{{4}}}, the second coefficient is {{{19}}}, and the last term is {{{-5}}}.



Now multiply the first coefficient {{{4}}} by the last term {{{-5}}} to get {{{(4)(-5)=-20}}}.



Now the question is: what two whole numbers multiply to {{{-20}}} (the previous product) &lt;font size=4&gt;&lt;b&gt;and&lt;/b&gt;&lt;/font&gt; add to the second coefficient {{{19}}}?



To find these two numbers, we need to list &lt;font size=4&gt;&lt;b&gt;all&lt;/b&gt;&lt;/font&gt; of the factors of {{{-20}}} (the previous product).



Factors of {{{-20}}}:

1,2,4,5,10,20

-1,-2,-4,-5,-10,-20



Note: list the negative of each factor. This will allow us to find all possible combinations.



These factors pair up and multiply to {{{-20}}}.

1*(-20)
2*(-10)
4*(-5)
(-1)*(20)
(-2)*(10)
(-4)*(5)


Now let&#39;s add up each pair of factors to see if one pair adds to the middle coefficient {{{19}}}:



&lt;table border=&quot;1&quot;&gt;&lt;th&gt;First Number&lt;/th&gt;&lt;th&gt;Second Number&lt;/th&gt;&lt;th&gt;Sum&lt;/th&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;1&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-20&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;1+(-20)=-19&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;2&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-10&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;2+(-10)=-8&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;4&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-5&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;4+(-5)=-1&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=red&gt;-1&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=red&gt;20&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=red&gt;-1+20=19&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-2&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;10&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-2+10=8&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;tr&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-4&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;5&lt;/font&gt;&lt;/td&gt;&lt;td  align=&quot;center&quot;&gt;&lt;font color=black&gt;-4+5=1&lt;/font&gt;&lt;/td&gt;&lt;/tr&gt;&lt;/table&gt;



From the table, we can see that the two numbers {{{-1}}} and {{{20}}} add to {{{19}}} (the middle coefficient).



So the two numbers {{{-1}}} and {{{20}}} both multiply to {{{-20}}} &lt;font size=4&gt;&lt;b&gt;and&lt;/b&gt;&lt;/font&gt; add to {{{19}}}



Now replace the middle term {{{19w}}} with {{{-w+20w}}}. Remember, {{{-1}}} and {{{20}}} add to {{{19}}}. So this shows us that {{{-w+20w=19w}}}.



{{{4w^2+highlight(-w+20w)-5}}} Replace the second term {{{19w}}} with {{{-w+20w}}}.



{{{(4w^2-w)+(20w-5)}}} Group the terms into two pairs.



{{{w(4w-1)+(20w-5)}}} Factor out the GCF {{{w}}} from the first group.



{{{w(4w-1)+5(4w-1)}}} Factor out {{{5}}} from the second group. The goal of this step is to make the terms in the second parenthesis equal to the terms in the first parenthesis.



{{{(w+5)(4w-1)}}} Combine like terms. Or factor out the common term {{{4w-1}}}


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Answer:



So {{{4w^2+19w-5}}} factors to {{{(w+5)(4w-1)}}}.



Note: you can check the answer by FOILing {{{(w+5)(4w-1)}}} to get {{{4w^2+19w-5}}} or by graphing the original expression and the answer (the two graphs should be identical).
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