<PRE><B>Question 181917</B>
x---money invested at 3%
y---money invested at 6%


1x+1y=6000----------b/c she has 6000 to invest
1.03x+1.06y=6315-------------b/c of the percent of investment and the final amount of money


solve eq. 1 for x
x=6000-y


plug that in to the second eq.
1.03(6000-y)+1.06y=6315


Distribute
6180-1.03y+1.06y=6315


Combine like terms
.03y=135


Solve for y
y=4500


x=6000-y
x=6000-4500
x=1500


Check answers:
x+y=6000
1500+4500=6000-------true

1.03(1500)+1.06(4500)=6315-----true
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Answers:
money invested at 3%----$1500
money invested at 6%----$4500</PRE>