Question 181872
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*[tex \LARGE \text{          }\math 12x^2-10x-8]


*[tex \LARGE \text{          }\math 3 \times 4 = 12]


*[tex \LARGE \text{          }\math (3 \times 2) + ( -4 \times 4) = 6 - 16 = -10]


*[tex \LARGE \text{          }\math -4 \times 2 = -8]


So:


*[tex \LARGE \text{          }\math 12x^2-10x-8 = (3x - 4)(4x + 2)]


Use FOIL to check.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
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