Question 181821
For Points P(-3,5) and Q(1,3) find (a)PQ and (b)the midpoint of PQ
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The easiest way to do these is to find the average of x and y separately.
(x1+x2)/2 = (-3+1)/2 = -1
(y1+y2)/2 = (5+3)/2 = 4
The midpoint is (-1,4)
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The length of PQ is (using Pythagoras):
{{{sqrt((diffy)^2 + (diffx)^2)}}}
={{{sqrt((3-5)^2 + (1+3)^2)}}}
={{{sqrt(4 + 16)}}}
= {{{sqrt(20)}}}
= {{{2sqrt(5)}}}
=~ 4.472