Question 181799
1=3x^2 + 2x 

answer: x=-1 or 1/3 

:
{{{3x^2+2x-1=0}}}
:
{{{(3x-1)(x+1)=0}}}factor
:
now set factors = to zero
:
so 3x-1=0-->3x=1-->x=1/3
:
....x-1=0-->x=1