Question 181666
6. f(x)= -3x^2+6x
---------------
a) find the y-int., the equation of the axis of symmetry, and the x-coordinate of the vertex
---
y-intercept: Let x = 0, then y = 0
---------
vertex: x = -b/2a = -6/(2*-3)) = 1; f(1)=-3 + 6 = 3
Vertex is (1,3)
---------
axis of symmetry: x = 1
----------------------------------------------
b)make a table of values that includes the vertex
(-1,-9),(0.0),(1,3),(2,0),(3,-9
---------------------------------------------------

c)use this information to graph the function 
{{{graph(400,300,-10,10,-10,10,-3x^2+6x)}}}
-------------------------------------------------
Cheers,
Stan H.