Question 181668
a) find the y-int., the equation of the axis of symmetry, and the x-coordinate of the vertex
b)make a table of values that includes the vertex
c)use this information to graph the function 
18) f(x)=x^2+2x+1:
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{{{y=(x+1)^2}}}
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vertex is at ({{{highlight(-1)}}},{{{0}}})
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line of symmetry is {{{highlight(x=-1)}}}
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to find y intercept set x to zero....{{{y=(0)^2+2(0)+1=1}}}
so y intercept is 1: (0,1)
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now just find a few more values of y for chosen x values
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such as when x=-1--->y=(-1)^2+2(-1)+1=0
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do this for as many points as you like to get a picture of the graph
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here is the graph
:
{{{graph(300,300,-10,10,-10,10,x^2+2x+1)}}}