Question 181623
I have a right triangle with side a=7 and side b=5. What is the value of sin A?
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You need to solve for "c" which I assume is the hypotenuse.
c = sqrt(7^2 + 5^2)

c = sqrt(49 + 25)

c = sqrt(74)
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If c is the hypotenuse, sin(A) = a/c = 7/sqrt(74)
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Cheers,
Stan H.