Question 181607
<font size = 6 color = "red"><b>MATHTUT'S SOLUTION USING METHOD THAT LAW OF SINES WAS DERIVED FROM</font></b>


ok!!!! we need to construct a line perpendicular to line BC coming from 
vertex A .
:
we will call that distance h. This splits the triange into 2 right triangles.
:
sin 46.2=h/7.3
:
h=7.3(.7218)=5.27
:
sin C=5.27/10.3={{{highlight(.5117)}}}