Question 181602
I assume the 1/2x is really 1/2x^2
:
{{{y=(1/2)(x^2-4x+4)-1-2}}}
:
{{{y=(1/2)(x-2)^2-3}}}
:
so vertex is currently at (2,-3)
:
if its moved up 3 units the vertex would be at (2,0)
:
{{{graph(300,300,-10,10,-10,10,(1/2)x^2-2x-1)}}}