Question 181601
{{{((14-2i))/((3+i))}}}
you multiply it by the conjugate of the denominator over itself
{{{((14-2i))/((3+i))}}} * {{{((3-i))/((3-i))}}} = {{{((42-14i-6i+2i^2))/((9+3i-3i-i^2))}}} = {{{((42-20i+2i^2))/((9-i^2))}}}
i^2 = -1, therefore
{{{((42-20i+2(-1)))/((9-(-1)))}}} = {{{((42-20i-2))/((9+1))}}} = {{{((40-20i))/(10)}}}
Divide 10 into both terms 
4 - 2i