Question 181559
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Let <i>w</i> be the width of the rectangle.  Then the length must be 2<i>w</i> - 5.  The perimeter is 2 times the length plus 2 times the width, so:


*[tex \LARGE \text {          }\math 2(2w - 5) + 2w = 26]


Solve for <i>w</i> to get the width, then multiply the width by 2 and subtract 5 to get the length.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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