Question 181487
{{{sqrt(7x)/sqrt(3)}}}. to rationalize multiply the numerator and denominator by {{{sqrt(3)}}}......square root of 3 times square root of 3 is 3
:
{{{sqrt(7x)sqrt(3)/3}}}
:
{{{highlight(sqrt(21x)/3)}}}
:
{{{root(3,x^2)/root(3,4)}}} multiply top and bottom by {{{root(3,4^2)}}}
:
{{{root(3,x^2)root(3,16)/4}}}because you would have {{{root(3,64)}}}in the denomiator and that equals 4.....because 64=4*4*4
:
{{{highlight(root(3,16x^2)/4)}}}