Question 181448
The level of thorium in a sample decreases by a factor of one-half every 2 million years. A meteorite is discovered to have only 8.6% of its original thorium remaining. How old is the meteorite? 
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A(t) = A(0)(1/2)^(t/2 million) where t is in million years
0.086A(0) = A(o)(1/2)^(t/2)
0.086 = (1/2)^(t/2)
Take the log of both sides to get:
(t/2)*log(1/2) = log(0.086)
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t = 2 
t = 2* 3.5395... 
t = 7.079.. million years
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Cheers,
Stan H.