Question 181446

Distance(d) equals Rate(r) times Time(t) or d=rt; r=d/t and t=d/r
Let t=time that elapses 'till they are the same distance from school
Distance Joseph is from school=5+4t
Distance Maya is from school=2+6t
The above two distances are the same, so:

Our equation to solve is:
5+4t=2+6t subtract 2 and also 4t from each side
5+4t-4t-2=2-2+6t-4t  collect like terms
3=2t  divide each side by 2
t=1.5 hr------------time that elapses 'till they are the same distance from school

Distance Joseph is from school=5+4*1.5 =11 mi
or
Distance Maya is from school=2+6*1.5=11 mi


Hope this helps----ptaylor