<PRE><B>Question 181436</B>
A chemist needs 10 L of a 50% alcohol solution. She must mix a 40% solution and a 65% solution. How many liters of each required to obtain what she needs?
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Equation:
alcohol + alcohol = alcohol
0.40x + 0.65(10-x) = 0.50*10

Multiply thru by 100 to get:

40x + 65(10-x) = 50*10

40x + 650 - 65x = 500

-25x = -150

x = 6 L (amt. of 40% solution in the mixture)
10-x = 4 L (amt. of 65% solution in the mixture)

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Cheers
Stan H.</PRE>