Question 181371
MX Labs needs to make 500 gallons of a 34% acid solution. The only solutions available are a 25% acid solution and a 50% acid solution. How may gallons of each solution should be mixed to make the 34% solution?
:
let x and y be the amount of 25% and 50% solutions used respectively
:
x+y=500.............eq 1
.25x+.5y=.34(500)...eq 2
:
rewrite eq 1 to x=500-y and plug it into eq 2
:
.25(500-y)+.5y=170
:
125-.25y+.5y=170
:
.25y=45
:
{{{highlight(y=180)}}}gallons of 50% solution
:
{{{highlight(x=500-y=500-180=320)}}}gallons of 25% solution