<PRE><B>Question 181304</B>
2 x nP2 + 50= 2nP2 is?

2[(n)!/(n-2)!] + 50 = [(2n)!/(2n-2)!]

2[n(n-1)(n-2)!/(n-2)!] + 50 = [(2n)(2n-1)(2n-2)!/(2n-2)!]

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2[n(n-1)] + 50 = (2n)(2n-1)

n(n-1) + 25 = n(2n-1)
n^2 - n + 25 = 2n^2 - n

n^2 = 25

n = 5
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Cheers,
Stan H.
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a. 3
b. 4
c. 5
d. 6
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