Question 181244
It's not an equation.
(x^2-x-6)/(x^2-2x-8) /  (x^2-9)/(x^2+7x+12)
=[(x-3)(x+2)]/[(x-4)(x-2)] *  [(x+4)(x+3)]/[(x+3)(x-3)] Factor and put in a times sign and invert the 2nd fraction.
=[(x+2)]/[(x-4)(x-2)] *  (x+4) Cancel.
=(x^2+6x+8)/(x^2-6x+8)
.
Ed