Question 181203
(1/3)^2-x=27^3+x
-------------------
I'll assume the exponents are (2-x) and (3+x).
(1/3)^(2-x) = 3^(x-2)
And, 27^(3+x) = 3^(9+3x) (27 = 3^3)
So,
3^(x-2) = 3^(3x+9)
x-2 = 3x+9
2x = -11
x = -11/2