<PRE><B>Question 181114</B>
two military squads are 26 miles apart. they plan to rendezvous at some
 intermediate point. if one squad hikes 2/3 mph faster than the other,
 and they meet in 3 hrs, what is the rate of the faster squad?
:
Let s = the speed of the faster squad
then
(s-{{{2/3}}}) = speed of the slow-pokes
:
The total dist of both squads = 26 mi, they both travel for 3 hrs:
write a distance equation dist = time * speed
:
3s + 3(s-{{{2/3}}}) = 26
Multiply what&#39;s inside the brackets
3s + 3s - 2 = 26
6s = 26 + 2
6s = 28
s = {{{28/6}}}
s = 14/3 or 4{{{2/3}}} mph is the speed of the faster squad
:
:
check solution by finding the dist traveled by each (slower squad = 4 mph)
3 * 4 = 12
3 * {{{14/3}}} = 14 
------------
Total 26 mi</PRE>