Question 181120
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*[tex \Large \text {          }\math \left(\frac {x^3 y^{(-4)}}{5x^6y^{(-8)}z^0}\right)^3]


I really can't tell where you went wrong on this.  


Remember a couple of rules:


*[tex \Large \text {          }\math a^{-n} = \frac {1}{a^n}]



*[tex \Large \text {          }\math \frac{a^n}{a^m} = a^{n-m}]



*[tex \Large \text {          }\math a^0= 1]


So, let's first get rid of all of the negative and zero exponents:


*[tex \Large \text {          }\math \left(\frac {x^3 y^{8}}{5x^6y^{4}}\right)^3]


The *[tex \Large y^{(-8)}] goes from the denominator to the numerator and becomes *[tex \Large y^8], *[tex \Large y^{(-4)}] goes from the numerator to the denominator and becomes *[tex \Large y^4], and finally, the *[tex \Large z^0] just goes away because it is equal to 1.


Next apply *[tex \Large \frac{a^n}{a^m} = a^{n-m}]:


*[tex \Large \text {          }\math \left(\frac {y^4}{5x^3}\right)^3]


One last rule:


*[tex \Large \text {          }\math a^n^m = a^{nm}], so:



*[tex \Large \text {          }\math \frac {y^{12}}{125x^9}]



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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