Question 181099
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The first thing to do is solve for <i>x</i>.  Since we know the perimeter of any polygon is the sum of the lengths of the sides, we can say:


*[tex \Large \text{             }\math (4x - 7) + 2x + 7 = 30 \ \ \rightarrow \ \  6x = 30 \ \ \rightarrow \ \ x = 5]


Now we know that side AB = 20 - 7 = 13, BC = 2 X 5 = 10, and AC = 7.


The size of any angle is proportional to the length of the opposite side.  So the smallest angle in this triangle is the angle oppostite side AC, namely angle B, and so on.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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