Question 181029
2x-5sqrt(x+2)=0
2x=5sqrt(x+2)
4x^2=25(x+2) square each side.
4x^2=25x+50
4x^2-25x-50=0
x=[5(sqrt(57)+5)]/8 is the only correct answer for this problem.
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Ed
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*[invoke solve_quadratic_equation 4, -25, -50]