Question 180733
Write the equation of variation:
{{{d = kt^2}}} where d = distance in feet and t = time in seconds. k = the constant of variation. To find the value of k, substiute d = 64 ft. and t = 2 secs.
{{{64 = k(2^2)}}} 
{{{64 = k(4)}}} Divide both sides by 4.
{{{k = 16}}}
The equation is now:
{{{d = 16*t^2}}} Substitute t = 10 secs.
{{{d = 16(10^2)}}}
{{{d = 16(100)}}}
{{{highlight(d = 1600)}}}feet.