Question 180776
Find two consecutive even integers such that the sum of their squares is 52.
.
Let x = 1st even integer
then
x+2 = 2nd even integer
.
x^2 + (x+2)^2 = 52
x^2 + x^2+4x+4 = 52
2x^2+4x+4 = 52
2x^2+4x-48 = 0
x^2+2x-24 = 0
(x+6)(x-4) = 0
.
x = {-6,4}
.
Solution: 4 and 6