Question 180749
First, let's find f(-1):


{{{f(-1)=x^2-2x+5}}} Start with the given function.



{{{f(-1)=(-1)^2-2(-1)+5}}} Plug in {{{x=-1}}}.



{{{f(-1)=1-2(-1)+5}}} Square {{{-1}}} to get {{{1}}}.



{{{f(-1)=1+2+5}}} Multiply {{{-2}}} and {{{-1}}} to get {{{2}}}.



{{{f(-1)=8}}} Combine like terms.



--------------------------------------------------------------------



Now let's find g(-1):



{{{g(x)=1/(1-1/x)}}} Start with the given function.



{{{g(-1)=1/(1-1/(-1))}}} Plug in {{{x=-1}}}.



{{{g(-1)=1/(1+1)}}} Reduce



{{{g(-1)=1/2}}} Add



---------------------------------------------


So {{{f(-1)=8}}} and {{{g(-1)=1/2}}}



{{{f(-1)+g(-1)}}} Move back to the main problem



{{{8+1/2}}} Plug in {{{f(-1)=8}}} and {{{g(-1)=1/2}}}



{{{16/2+1/2}}} Multiply 8 by {{{2/2}}}



{{{(16+1)/2}}} Combine the fractions.



{{{17/2}}} Add



=====================================================


Answer:



So {{{f(-1)+g(-1)=17/2}}}