Question 180756
{{{(((x^2+4x)/(x+3)))/(8x^4+32x^3)}}}
Invert the second divisor and multiply:
{{{((x^2+4x)/(x+3))*(1/(8x^4+32x^3))}}} Factor where possible:
{{{(x*cross((x+4))/(x+3))*(1/8x^3cross((x+4)))}}} Cancel as indicated:
{{{(cross(x)/(x+3))*(1/(8x^2cross((x))))}}} Cancel an x:
{{{1/((x+3)(8x^2))}}} = {{{highlight(1/(8x^3+24x^2))}}}