<PRE><B>Question 180751</B>

(f-g)(x) , given that f(x)= 1-x/2+x, g(x)= 2x-3/x-2 is ?

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(f-g)(x) = f(x) - g(x)

= (1-x)/(2+x) - (2x-3)/(x-2)

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Rearrange:

= -(x-1)/(x+2) - (2x-3)/(x-2)

= [-(x-1)(x-2) - (2x-3)(x+2)] / [x^2-4]

= [-(x^2-3x+2) -(2x^2+x-6)] / [x^2-4]

= [-3x^2 + 2x + 4] / [x^2-4]

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Cheers,
Stan H.</PRE>