Question 180666
{{{f(x)=abs(x^2-10x+1)}}}
{{{f(-3)=abs((-3)^2-10(-3)+1)}}}
{{{f(-3)=abs(9+30+1)}}}
{{{f(-3)=abs(40)}}}
{{{f(-3)=40}}}
.
.
.
{{{f(f(3))=f(40)=abs(40^2-10(40)+1)}}}
{{{f(f(3))=abs(1600-400+1)}}}
{{{f(f(3))=abs(1201)}}}
{{{f(f(3))=1201}}}