Question 180540
re write these in slope intercept form y=mx+b
:
-18y=3x+6--->y=(-1/6)x-(1/3)........eq 1
:
-y=-6x+14--->y=6x-14................eq 2
:
The slope in eq 1 is -1/6 and the slope in eq 2 is 6. These are negative recipricals of each other therefore these are 
:
perpendicular lines