Question 180522
Can I have help in finding the equation of the line passing through (1,1) and (4,6) and putting answer in slope-intercept form. 
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I'll do it 2 different ways, you can pick the one you like.
1st method:
Find the slope, m
m = (diff in y)/(diff in x)
m = (6-1)/(4-1)
m = 5/3
Then use either point:
y-y1 = m*(x-x1) where (x1,y1) is the point
y-1 = (5/3)*(x-1)
y-1 = (5/3)x - 5/3
y = (5/3)x - 2/3
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2nd method:
|x y 1|
|1 1 1| = 0
|4 6 1|
x*(1-6) - y*(1-4) + 6-4 = 0
-5x + 3y + 2 = 0
3y = 5x - 2
y = (5/3)x - 2/3