Question 174813
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The sum of the interior angles of any polygon, regular or otherwise, is given by *[tex \Large (n - 2) \times 180] degrees where <i>n</i> is the number of sides forming the polygon.  The number of interior angles in any polygon is equal to the number of sides forming the polygon.


Since you are dealing with a regular polygon of 100 sides, it has 100 equal length sides and 100 interior angles of equal measure, so to find the measure of one of the angles, calculate the sum of all of them and divide by the number of angles.  In other words, evaluate:


*[tex \Large \text {          } \math \frac {(100 - 2)(180)}{100}]


It might be of interest to note that no matter how many sides you choose, the interior angles will always be less than 180 degrees.  You might want to think about the limiting shape as the number of sides gets very large.


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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