Question 180480
My question: Am I on the right track and/or if not can you please show me how to set up the hypothesis test and solve for it? 
I got this: 
Female: 272/15 = 18.133
Male: 284/15 = 18.933
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Comment: I'm going to assume your mean calculations are correct.
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You need a 2-Sample Z-test addessing the question of difference between
the attitude of the sexes.
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H0: u(men)-u(women) = 0
H1: u(men)-u(women) is not 0
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Assuming alpha = 5% the Rule for the 2-Sample test is "Reject Ho if
test statistic is Less than -1.96 or greater than +1.96.
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Small Sample 
Test statistic: (18.133 – 18.933)/Sqrt [30(squared)*(1 over 15 + 1 over 15) = (0.8) / 900 * 2 over 15 = 120 
(-0.8)/Sqrt 120 = (-0.8) / 10.954 = 0.073
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Comment: I can't follow you here:
I got the following:

t.s. = (difference of sample means)/sqrt[(s(men))^2/15 + (s(women))^2/15]
I ran it on a TI-calculator and got z = -0.073..
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If that is right, since t.s. is not in the reject interval, Fail to reject
Ho.  There is no statistical difference in attitude toward CIELO by the
sexes.
 

Large Sample 

18.133 – 18.933/Sqrt 30(squared) / 30(squared)over 15 / 30 (squared) over 15 
= (0.8)/900 over 15 + 900 over 15 
= (0.8)/ 60+60 = (0.8) / 120 = 0.006 

Q: I am not sure if these are the right samples to use or if I should use a paired “t” sample? (below) 

Whether you use "t" or "z" depends on your textbook requirements or your
professor's directions.  By the way, what is the textbook and what is the
chapter and problem number?
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Comment: I would appreciate your feedback on these comments.  Do they
help? Are they confusing or contradictory?
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Cheers,
Stan H.



15
30 / sqrt (?) 
Thank you