Question 180443
Ad^2=k where k is a constant
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lets find k
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we are given A=2 and d=3
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{{{2(3)^2=k}}}
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so our constant k =18
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Ad=18
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now lets find A when d=.5.....remembering that in an inverse relationship when one variable increases the other decreases and vice versa. In this instance d is decreasing from 3 to .5 so we would expect A to increase
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{{{A(.5)^2=18}}}
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{{{highlight(A=72)}}}newtons....and just like we knew A increased from 2 to 12