Question 180342
Solve the equation 3/ (x-4) + 5 / (x+4) = 7x / (x^2 -16)
{{{(3/(x-4)) + (5/(x+4)) = 7x/(x^2-16)}}}
{{{(x^2-16)}}} is the DEN since it's (x-4)*(x+4)
{{{(3/(x-4)) + (5/(x+4)) = 7x/(x^2-16)}}}
{{{3(x+4)/(DEN) + 5(x-4)/(DEN) = 7x/(DEN)}}}
Multiply thru by the DEN
3(x+4) + 5(x-4) = 7x
3x+12 + 5x-20 = 7x
8x-8 = 7x
x = 8