Question 25187
6+{{{5/y}}} = y-{{{2/y}}}
First get like terms together, so subtract y from both sides;
6+{{{5/y}}}-y=y-{{{2/y}}}-y
6+{{{5/y}}}-y=-{{{2/y}}}
Now subtract 5y from both sides;
6+{{{5/y}}}-y-{{{5/y}}}=-{{{2/y}}}-{{{5/y}}}
6-y=-{{{7/y}}}
Multiply -y to both sides;
6-y(-y)=-{{{7/y}}}(-y)
-6y+{{{y^2}}}=7
Now subtract 7 from both sides;
{{{y^2}}}-6y-7=0
Factor;
(y-7)(y+1)=0
y-7=0  y+1=0
y=7 or y=-1
Hope you understand
=)