Question 180333
Determine Algebraically weather the function is even, odd, or neither. 
h(x)= x / (x^2-1) 
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h(-x) = (-x)/[(-x)^2-1] = -x/(x^2-1
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-(h(-x)) = x/(x^2-1)
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Since h(x) = -h(-x) the function is symmetric to the origin.
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{{{graph(400,300,-10,10,-10,10,x/(x^2-1))}}}
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Cheers,
Stan H.