Question 180318
Given the two bases a and b, and the height h of a trapezoid, the area is given by
{{{A=1/2 (a+b)/h}}}

so the area of the trapezoid you've given is {{{(1/2)(25+7)9=(1/2)(34/9)=17/9 sq. meters

In any parallelogram, opposite sides have the same length. So the perimeter of the parallelogram is 2(6.5+3.5)=2(10)=20 m

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