Question 180264
Note: *[Tex \LARGE \left(x_{1}, y_{1}\right)] is the first point *[Tex \LARGE \left(2,6\right)] and *[Tex \LARGE \left(x_{2}, y_{2}\right)] is the second point *[Tex \LARGE \left(4,-1\right)].



{{{m=(y[2]-y[1])/(x[2]-x[1])}}} Start with the slope formula.



{{{m=(-1-6)/(4-2)}}} Plug in {{{y[2]=-1}}}, {{{y[1]=6}}}, {{{x[2]=4}}}, and {{{x[1]=2}}}



{{{m=(-7)/(4-2)}}} Subtract {{{6}}} from {{{-1}}} to get {{{-7}}}



{{{m=(-7)/(2)}}} Subtract {{{2}}} from {{{4}}} to get {{{2}}}



So the slope of the line that goes through the points *[Tex \LARGE \left(2,6\right)] and *[Tex \LARGE \left(4,-1\right)] is {{{m=-7/2}}}