Question 180227
<font face="Times New Roman" size="+2">


*[tex \Large \text{          }\math 3x-y = -2]
*[tex \Large \text{          }\math y = 2x+3]  


Just substitute the expression given as equal to <i>y</i> in the 2nd equation into the 1st equation, thus:


*[tex \Large \text{          }\math 3x-(2x+3) = -2]


Now solve for <i>x</i>.  Once you have the value for x, substitute that into either of the original equations (the 2nd one gives you easier arithmetic) and compute the value of <i>y</i>.




John
*[tex \LARGE e^{i\pi} + 1 = 0]
</font>