<PRE><B>Question 180199</B>
ok. so first we need to rewrite this in slope intercept form which is 
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y=mx+b where m is the slope and b is the y intercept(0,b).
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I will have to assume that the -8 is really =8 since we need an equals somewhere
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3x-2y=8
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-2y=-3x+8....subtracted 3x from both sides
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y=(3/2)x-4...divided all terms by -2
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so slope is 3/2 and the y intercept is -4 (0,-4)
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so we start by plotting the point (0,-4). This is a positive slope so we move
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3 units up and 2 units to the right(plot that point) then draw a line thru both those points and there ya have it.
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should look like this when your done. BTW the other point will end up at (2,-1)
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{{{graph(300,300,-10,10,-10,10,(3/2)x-4)}}}</PRE>