Question 180241
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Let <i>w</i> be the width.  Then we know the length is 2.7<i>w</i>.


Since we know the perimeter of a rectangle is given by *[tex \Large P = 2L + 2W] and we are given that the perimeter is 72.52 feet, we can write:


*[tex \Large \text{          }\math 2(2.7w) + 2w = 72.52]


Just solve for <i>w</i> to get your answer.



John
*[tex \LARGE e^{i\pi} + 1 = 0]
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