Question 180130
{{{ -((8a^3)/27)^(-(4/3))}}} (I hope this is right)
I note that {{{27 = 3^3}}}
and {{{8 = 2^3}}}
{{{ -(((2a/3)^3)^(-(4/3)))}}}
{{{-((2a/3)^(-4))}}}
{{{-(3/(2a))^4}}} answer
check: suppose {{{a = 3}}}
{{{-(3/(2*3))^4}}} 
{{{-(1/2)^4}}}
and
{{{ -((8a^3)/27)^(-(4/3)))}}}
{{{ -(8^(-(4/3)))}}}
{{{ -(1 /(8^(4/3)))}}}
{{{-(1/(2^4))}}}
{{{-(1/2)^4}}}
OK