Question 180111
1.)The cable is the hypotenuse of a right triangle (HYP). 
The height of the pole is one leg(OPP). 
The length from the pole to where the cable touches the ground is the other leg(ADJ).
The angle, A, that the cable makes with the ground has the relation
{{{sin(A)=OPP/HYP=22/30.4=0.7237}}}
{{{A=
46.4}}}
Angle A is 46.4 degrees.
{{{drawing( 300, 300, -5, 5, -5, 5,
line(-4,0,2,0),
line(-4,4,-4,0),
locate(0,0.7,A),
locate(-3.8,2,22m),
locate(-.5,2.5,30.4m),
line(-4,4,2,0))}}}


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2.) The length of ADJ can be calculated from the Pythagorean theorem,
{{{HYP^2=OPP^2+ADJ^2}}}
{{{30.4^2=22^2+ADJ^2}}}
{{{ADJ^2=924.16-484=440.16}}}
{{{ADJ=20.98}}}
If I reduce that distance by 1 m, it would be 19.98.
The angle remains the same. 
The new adjacent side is now 19.98. 
The new opposite side can be calculated using,
{{{tan(A)=OPP/ADJ}}}
{{{tan(46.4)=OPP/19.98}}}
{{{OPP=19.98*tan(46.4)}}}
{{{OPP=19.98*1.050}}}
{{{OPP=20.98}}}
The cable height 1 meter from the pole would be 20.98m.
{{{drawing( 300, 300, -5, 5, -5, 5,
line(-4,0,2,0),
line(-4,4,-4,0),
locate(0,0.7,46.4),
line(-3.7,0,-3.7,3.8),
line(-4,4,2,0),



locate(0,-3.8,46.4),
line(-3.7,-4.5,-3.7,-.5),
line(-3.7,-0.5,2,-4.5),
line(-3.7,-4.5,2,-4.5),
locate(-3,-3.8,19.98)
)}}}
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