<PRE><B>Question 180186</B>
Two metal alloys, one containing 26% copper and the other containing 54%copper are to be mixed together to get 210 oz of an alloy that is 30% copper. How much of the alloy containing 26% copper should be used?
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Equation:
copper + copper = copper
0.26x + 0.54(210-x) = 0.30*210

Multiply thru by 100 to get:
26x + 54*210 - 54x = 30*240

-28x = - 14*240

x = 120 oz (amt. of 26% alloy in the mixure)
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Cheers,
Stan H.</PRE>