Question 180047
{{{x-2sqrt(x)=8}}}
:
{{{-2sqrt(x)=8-x}}}subtracted x from both sides
:
{{{4x=(8-x)^2}}}squared both sides
:
{{{4x=64-16x+x^2}}}
:
{{{x^2-20x+64=0}}}
:
{{{(x-16)(x-4)=0}}}
:
x=4 and 16
:
4 is an extraneous root which occurs at times when squaring, so we throw it out as a solution
:
x=16