Question 179785
:
y ={{{1/1800}}}(x-600)(x+600)  x & y are measured in meters
:
1)how wide is the crater if y=0 and what is the depth of the crater?
:
Multiply equation by 1800
(x+600)(x-600) = 0
x = +600, x = -600
Difference between intercepts = 1200 meters
:
Find the min using the original equation
:
y ={{{1/1800}}}(x-600)(x+600) 
:
y = {{{(x^2 - 360000)/1800}}}
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y = {{{(x^2/1800)}}} - {{{(360000/1800)}}}
:
y = {{{(x^2/1800) - 200}}}
:
difference of squares so axis of symmetry is 0 
:
in the above equation, y = -200, when x = 0
: 
depth of the crater = 200 meters:
Like this
{{{ graph( 300, 200, -700, 700, -250, 100, x^2/1800 -200)}}}
:
Crater is 1200 m wide and 200 m deep