Question 179723
Angel is twice as old as Gavin. In 3 years, Angel will be 13 years less than twice as old as Gavin. Find their ages now.
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Angel's age now = A
Angel's age 3 years from now = A+3
Gavin's age now = G
Gavin's age 3 years from now = G+3
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>>...Angel is twice as old as Gavin...<<
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That says A = 2G
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>>...In 3 years, Angel will be 13 years less than twice as old as Gavin...<<
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That says:

(A+3) is 13 years less than twice (G+3)

or

A+3 = 2(G+3) - 13
A+3 = 2(G+3) - 13
A+3 = 2G+6-13
A+3 = 2G-7
  A = 2G-10



So we have the system:

{{{system(A=2G,A=2G-10)}}}

Substituting 2G for A in the second equation:

{{{2G=2G-10}}}

Subtract 2G from both sides

{{{0=-10}}}

So the system is inconsistent.  There is no solution.

Edwin</pre>