Question 179778
{{{w^2-12w+c}}} 
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remember the rule: you take 1/2 of the w term and then square that value
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so in our case we have 12/2=6. We then take 6 and square it which results
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in 36
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so c=36
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we are left with {{{w^2-12w+36}}}
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which when factored would yield the perfect square {{{(w-6)^2}}}